If you are saying the resistance must be between 3,000Ω and 7,000Ω, I can see 80KΩ + 3.3KΩ resistors in parallel = 3169Ω (between range). But still don't understand the relationships and the wording used in your post.
What's the meaning of "present a load"?
And of "not enough to pull the voltage (@ the quoted load) up"?
If resistors cause a voltage drop, reducing the resistance by adding another resistor in parallel will make the drop smaller, hence closer to 5V. Is this the way to understand it?
I knew about pull-up resistors used to prevent too much current going to ground, while allowing and input to stay high (Vcc).
But in this context their use seems a bit different, they are used with an "open-collector" output (according to TSOP IC datasheet).