problem with controlling LCD 16x2 with PIC 16f877

wanbong · Sep 23, 2008

pic16f877 lcd

hi guys, I'm just an newbie with PIC
I'm trying to control the LCD 16x2 (model SC1602-B) with a PIC 16f877

The simulation of my code on the Proteus 7 can run but when I work with real thing it couldn't print out anything

please help me out, below is my code

/*

* PORTB bits 0-3 are connected to the LCD data bits 4-7 (high nibble)
* PORTA bit 2 is connected to the LCD RS input (register select)
* PORTA bit 3 is connected to the LCD EN bit (enable)
*
* To use these routines, set up the port I/O (TRISA, TRISB) then
* call lcd_init(), then other routines as required.
*
*/

//Define compiler error message.
#ifndef __CPU_16F877__
#error "This program is tailored for PIC16F877 controller"
#endif

//Include required header files here.
#include "io16f877.h" //the hardware register definition file.
//-----------------------------------------------------------------delay---------------------------------------------------
//---------------------------------------------------------------------------------------------------------------------------
void DelayUs(int count)
{
int i;
int j;
for(i=0;i<count;i++)
{
for(j=0;j<5;j++);
//This for loop has 5 NOPs & wastes 1 uS for our PIC clock frequency of 20MHz.
}
}

void DelayMs(int count)
{
int i;
for(i=0;i<count;i++)
{DelayUs(4000);}
}
//---------------------------------------------------------------------------------------------------------------------------
//-----------------------------------------------------------------------------------------------------------------------------

#define LCD_RS RA2 // Register select
#define LCD_EN RA3 // Enable

#define LCD_STROBE ((LCD_EN = 1),(LCD_EN=0))

/* write a byte to the LCD in 4 bit mode */

void
lcd_write(unsigned char c)
{
PORTB = (PORTB & 0xF0) | (c >> 4);
LCD_STROBE;
PORTB = (PORTB & 0xF0) | (c & 0x0F);
LCD_STROBE;
DelayUs(40);
}

/*
* Clear and home the LCD
*/

void
lcd_clear(void)
{
LCD_RS = 0;
lcd_write(0x1);
DelayMs(2);
}

/* write a string of chars to the LCD */

void
lcd_puts(const char * s)
{
LCD_RS = 1; // write characters
while(*s)
lcd_write(*s++);
}

/* write one character to the LCD */

void
lcd_putch(char c)
{
LCD_RS = 1; // write characters
PORTB = (PORTB & 0xF0) | (c >> 4);
LCD_STROBE;
PORTB = (PORTB & 0xF0) | (c & 0x0F);
LCD_STROBE;
DelayUs(40);
}

/*
* Go to the specified position
*/

void
lcd_goto(unsigned char pos)
{
LCD_RS = 0;
lcd_write(0x80+pos);
}

/* initialise the LCD - put into 4 bit mode */

void
lcd_init(void)
{
LCD_RS = 0; // write control bytes
DelayMs(15); // power on delay
PORTB = 0x3; // attention!
LCD_STROBE;
DelayMs(5);
LCD_STROBE;
DelayUs(100);
LCD_STROBE;
DelayMs(5);
PORTB = 0x2; // set 4 bit mode
LCD_STROBE;
DelayUs(40);
lcd_write(0x28); // 4 bit mode, 1/16 duty, 5x8 font
lcd_write(0x08); // display off
lcd_write(0x0F); // display on, blink curson on
lcd_write(0x06); // entry mode
}
void IniPort()
{
ADCON1=0x06;
TRISA=0x00;
TRISB=0x00;
PORTA=0x00;
PORTB=0x00;

}

char text[]="len di\n";
int count=0;
void main(void)
{
IniPort();
lcd_init();
while (text[count]!='\n')
{
lcd_putch(text[count]);
count++;
}
DelayUs(100);
while(1){}
}

Added after 5 hours 48 minutes:

after I ground all the unused pins, there is array of blocks appear in the second line the LCD still can not print out anything

pasicr · Sep 23, 2008

io16f877.h

Hi, I think you have problem with pin connection,
for example, I have two tipe of 1602-b LCD,
look on attached pictures,
regards

wanbong · Sep 24, 2008

pic lcd 16x2

here is my pins connection
1 GND
2 Vdd
3 GND
4 RA2
5 GND
6 RA3
7->10 GND
11->14 RB0->RB3
15 5V
16 GND

blueroomelectronics · Sep 24, 2008

connection between pic16f877 with 16x2 lcd

You need an adjustable contrast, put a 10K pot between power, gnd and pin 3 (pin 3 should not be ground but often just slightly above. it can even be negative on some old LCDs) check the datasheet.

laktronics · Sep 25, 2008

pic lcd problem

Hi,

1. In lcdinit, change

PORTB = 0x3; // attention

to 0x2 .

2. lcd RAM address is not inited in lcdinit ( By command 0x01 , for CLR display) nor called in the Main function.

3. R/W- pin to be grounded

Regards,
Laktronics

wanbong · Sep 26, 2008

lcd 16x2 4bit

thanks for all ur reply finally my LCD can work
the prob is that I connected RS pin wrongly
the point that blueroomelectronics is also correct. If we don't put a potentionmeter for changing the contrast sometimes we can not see the displayed character

Chrono Helix · Feb 19, 2009

lcd (16x2 @ 4 bit) c programming

I'm working on something similar, but I'm having trouble getting my LCD (Sanyo DM1622, datasheet at http://www.datasheetcatalog.com/datasheets_pdf/D/M/1/6/DM1622.shtml) to display anything besides 2 rows of 16 squares. Mainly I think it's the initialisation process that's tripping me up.

Pin setup is as follows:
1 GND
2 +5V
3 -5V
4 RA2
5 GND
6 RA3
7->10 GND
11->14 RB0->RB3
15 5V
16 GND

I don't understand some parts of the OP's code.

void IniPort()
{
ADCON1=0x06;
TRISA=0x00;
TRISB=0x00;
PORTA=0x00;
PORTB=0x00;

}

lcd_init(void)
{
LCD_RS = 0; // write control bytes

Why do you need to set LCD_RS = 0 in lcd_init again? When you set PORTA=0x00 in IniPort, isn't LCD_RS already set to 0?

void
lcd_init(void)
{
LCD_RS = 0; // write control bytes
DelayMs(15); // power on delay
PORTB = 0x2; // attention! Was originally 0x3, but laktronics suggested changing it to 0x2. Why?
LCD_STROBE; Step 1
DelayMs(5);
LCD_STROBE; Step 2
DelayUs(100);
LCD_STROBE; Step 3
DelayMs(5);
PORTB = 0x2; // set 4 bit mode
LCD_STROBE; Step 4
DelayUs(40);
lcd_write(0x28); // 4 bit mode, 1/16 duty, 5x8 font
lcd_write(0x08); // display off
lcd_write(0x0F); // display on, blink curson on
lcd_write(0x06); // entry mode
}

Right now I'm interpreting the lcd_init function as doing the following.

Step 1:
DB7 DB6 DB5 DB4 DB3 DB2 DB1 DB0
0 0 1 0 ? ? ? ?
Nothing happens yet, only first 4 bits written

Step 2:
DB7 DB6 DB5 DB4 DB3 DB2 DB1 DB0
0 0 1 0 0 0 1 0
The LCD is given the command to do a function set of 4 bits, 1 line, 5*7 dots.

Step 3
DB7 DB6 DB5 DB4 DB3 DB2 DB1 DB0
0 0 1 0 ? ? ? ?
Nothing happens yet, only first 4 bits written

Step 4
DB7 DB6 DB5 DB4 DB3 DB2 DB1 DB0
0 0 1 0 0 0 1 0
The LCD is given the command to do a function set of 4 bits, 1 line, 5*7 dots.

From the information I get from this page http://www.8051projects.net/lcd-interfacing/lcd-4-bit-programming.php
the initialisation for 4-bit mode for a similar LCD is as follows

void lcd_reset()
{
lcd_port = 0xFF;
delayms(20);
lcd_port = 0x03+LCD_EN;
lcd_port = 0x03;
delayms(10);
lcd_port = 0x03+LCD_EN;
lcd_port = 0x03;
delayms(1);
lcd_port = 0x03+LCD_EN;
lcd_port = 0x03;
delayms(1);
lcd_port = 0x02+LCD_EN;
lcd_port = 0x02;
delayms(1);
}

How do you have
lcd_port = 0xFF;
when you're only using 4 bits?

firevsice55 · Nov 16, 2010

Re: lcd (16x2 @ 4 bit) c programming

I am also facing the same problem

nandhu015 · Nov 16, 2010

Re: lcd (16x2 @ 4 bit) c programming

firevsice55 said:
I am also facing the same problem

Why are you digging out a year old problem and saying "same problem".

Instead you can start a new thread explaining your problem.

AliRazoR · Nov 16, 2010

**broken link removed**

storage · Feb 21, 2011

Can someone tell me what was wrong in wanbong's coding and what was changed? I would like a full correct coding of it if possible. Thanks.

asharwahid · Nov 20, 2011

CSS C compiler has the built in function of controlling LCD.
16x2 LCD interfacing with PIC-16f877a is available.
To get this and to get complete help regarding this feel free to contact on asharwahid@yahoo.com

problem with controlling LCD 16x2 with PIC 16f877

wanbong

Newbie level 5

pasicr

Advanced Member level 1

romel_emperado

wanbong

Newbie level 5

blueroomelectronics

Advanced Member level 5

laktronics

Banned

wanbong

Newbie level 5

newtonsjr

Chrono Helix

Newbie level 1

firevsice55

Junior Member level 1

nandhu015

Advanced Member level 5

AliRazoR

Advanced Member level 4

Teruteru314

romel_emperado

storage

Junior Member level 1

asharwahid

Newbie level 3

Attachments

Similar threads

problem with controlling LCD 16x2 with PIC 16f877

Newbie level 5

Advanced Member level 1

Newbie level 5

Advanced Member level 5

Banned

Newbie level 5

Newbie level 1

Junior Member level 1

Advanced Member level 5

Advanced Member level 4

Junior Member level 1

Newbie level 3

Attachments

Similar threads

Privacy & Transparency

Privacy & Transparency