Problem with calculating the cascade realization of a FIR??

cascade fir matlab

Hello, I've been a lot of time trying to know how to develope a cascade realization of this FIR transfer function with MATLAB:

H(z)=-0.24+0.184z^-1+0.448z^-2+1.296z^-3+0.4448z^-4+0.184z^-5-0.24z^-6;

I read that I have to use the function latc2tf of MATLAB, I just don´t know how to use it, I intriduce the coefficients but it gives me an error.

COuld anyone help me or send me to a webpage with good examples??

Thank You very much!!

Re: Problem with calculating the cascade realization of a FI

Thank you very much mathuranatham!

But I tried and get this:

>> b=[-0.24 0.184 0.448 1.296 0.4448 0.184 -0.24]

b =

-0.2400 0.1840 0.4480 1.2960 0.4448 0.1840 -0.2400

>> b=b./-0.24

b =

1.0000 -0.7667 -1.8667 -5.4000 -1.8533 -0.7667 1.0000

>> k=tf2latc(b)
??? Error using ==> d:/matlab/toolbox/signal/signal/private/levdown
At least one of the reflection coefficients is equal to one.
The algorithm fails for this case.

Error in ==> D:\matlab\toolbox\signal\signal\poly2rc.m
On line 48 ==> [a,e(k)] = levdown(a,e(k+1));

Error in ==> D:\matlab\toolbox\signal\signal\tf2latc.m (fir2latc)
On line 151 ==> K = poly2rc(num);

Error in ==> D:\matlab\toolbox\signal\signal\tf2latc.m
On line 54 ==> [K,V,msg] = fir2latc(num,den,phaseOpt,nargout);

This is the same problem that I was having before.