Problem with C code of array

[london]

I wrote a programing using array that
int Letter[]
....
....
switch key
{
case 1 : Letter[]={2,1,0}; break;
case 2 : Letter[]={3,2,3}; break;
}

but compiler indicate error on Letter[]={x,x,x} line. Why is that? can u correct me?

 

[yasser_shoukry]

Re: Abt C code

The array initialization block - {.... , .... , ....} - can be used only on the same line of the array declartion, e.g:

int array[]={1,2,3}; /*correct*/

but

int array[];
array[]={1,2,3}; /*wrong*/

so you can not use the fragent you wrote

case 1 : Letter[]={2,1,0}; break;
case 2 : Letter[]={3,2,3}; break;

instead you have to assign each element of the array individually, e.g:

case 1: Letter[0]=2;
Letter[1]=1;
Letter[2]=0;
break;
case 2: ...........

or make use of a for loop if you can.

Another two comments on your code:
1-While declaring your array , you have to declare its size unless you are using the initialization block - which is {.... , ..... , ..... }
e.g

int array[3] ; /* correct */
int array[]; /* wrong */

int array[3]={1,2,3}; /*correct*/
int array[]={1,2,3}; /* also correct*/

2-Do not forget the parentheses in the switch statement , i.e

switch (expression)
{
....
....
....
}

Hope I was able to help. Good luck!