Hi all,
I'm sorry if i cause any inconveviences to anyone, i have a question but i don't have an exact answer,
the question is "Why the capacitor cannot be connected to the load of the inverter?", i tried to get an answer,
does that relates to the charge of the capacitor :?: , i mean by that does the capacitor charge will affect on the output of the inverter ?
Thanks,
Yousef Omran.
Sorry, the inverter is voltage source inverter type, i saw in Rashid book, The VSI generates an ac output voltage waveform composed of discrete values (high dv=dt); therefore, the load should be inductive at the harmonic frequencies in order to produce a smooth current waveform. A capacitive load in the VSIs will generate large current spikes.
Why did that occure ?
and why the value of (dv/dt) is high?
Thanks.
Again you didn't attach a schematic of the inverter you are talking about.
Maybe it is a simple square-wave inverter. The square-waves have a high dv/dt because the output transistors switch completely on and completely off very quickly. A capacitive load will draw high momentary currents.
Thanks Audioguru, but the question NOW why the capacitor draws a high momentary current, is there any mathematical explaination which descrices that?
very thatnks to you.
The rapidly rising voltage causes a high charging current in the load capacitor.
The rapidly falling voltage causes a high discharge current in the load capacitor.