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please help in making coil

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dodo_8008

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please i want the law used to make a coil with certain impediance

by determining the thickness of the wire, the radius of the core, the kind if the core,
the length of coil .......please i want this with drawing if available...if not available the formula is ok


please i want your reply in shortest time


thanks
 

One of the simplest coils is a single-layer close-wound air-cored coil ..
Its inductance can be calculated using the so called Wheeler's Formula:
**broken link removed**
and its impedance is:
Z=ωL=2Πf * L

Regards,
IanP
 

Hello,

If you do a search using the phrase: "inductance calculator", for example you can find some online calculators; e.g.:

**broken link removed**

**broken link removed**

There are many more, including specialized calculators for tesla coil inductors, for example:

http://www.classictesla.com/fantc/fantc.html

Lastly, attached is a zip file with two PDFs (not scanned) regarding inductance calculations.
 

FIRST THANKS

ALL YOUR REPLIES DIDNOT CONTAIN THE DISTANCE BET. EACH TURN

PLEASE HELP
 

Perhaps "Wheeler's Formula" would be of help?

Single layer air core solenoid:

L (uH) = n^2 * r^2 / (9 * r + 10 * l)

where

r = coil radius in inches
l = coil length in inches
n = number of turns

**broken link removed**
 

I WOULD LIKE TO THANK YOU,,,,BUT THE FORMULLA DIDNOT MENTION ABOUT THE THICKNESS OF THE WIRE ,EX:1MM,,0.2MM,,,,....THINGS LIKE THAT
 

With all due respect, the Wheeler Formula contains "things like that" but they are hidden in the diameter of the coil (internal diameter + radius of wire) and in its length (munber of turnes + gaps between them) .. see picture below ..
Once again, I encourage you to look in:
**broken link removed**
and carefully read conditions and you will find "things like that" ..

Regards,
IanP
 

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