Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.
...page 7 (and many others) shows the bias of the PIN diodes...at page 8 is just a symbolic schematic, to show the main configuration of the circuit.
Whatever configuration is used (switch, attenuator, modulator, phase shifter), a PIN diode needs a bias circuit.
I am not familiar to rf circuits.
There is a circuit in foundation of microwave eng. which is easy to implement because of microstrips so you dont have to
interest inductors or capacitors.
I designed it for 45 degree phase shift but ads simulates properly if there is bias or not.
The point i dont get it is what should i connect to upper bias point ? -10 V? Nothing?
Yes, in your situation have to feed the circuit with a negative voltage (positive to the ground), but this needs to be done using a series resistor for current limiting.
1N5767 is a medium power PIN diode and the bias current (function of the RF resistance) could be between 1mA and 100mA.
In your situation because the diode is used as a switch, have to provide high current for low RF resistance. So, the series bias resistor and the DC supply gives you the current through the PIN diode.
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.