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Phase Locked Loop Theory

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Paul678

Newbie level 6
From this paper:

http://www.elenota.pl/datasheet-pdf/88472/National-Semiconductor/AN-1001

"When designing for a higher phase margin you trade off
higher stability for a slower loop response time and less
attenuation of the Reference Frequency."

Is this true for ALL PLLs?

And it would seem the converse is true with the loop
bandwidth, because a wider, higher loop bandwidth
gives you a faster acquisition time (Settling time), but
may make the loop less stable, and will attenuate the
Reference spurs less.

Thoughts?

Not a PLL expert here but yes control loop BW has those attributes you
mention.

This might be useful, still relevant after all these years.

Paul678

Newbie level 6
Ok, thanks everyone. Banerjee's book is very good.

But is there a typo on page 42, in terms of where the zero and poles
are in transfer function 7.1, on page 41? (See attached pic)

Last edited by a moderator:

KlausST

Super Moderator
Staff member
Hi,

off-topic:
instead of shooting a photo (6.06MB for half a page) from a computer screen of a PDF (6,18MB for all 500 pages)
or a screenshot with reduced picture quality (0.04MB jpg)

or a screenshot with perfect qualtiy (0.10MB png)

Remember this is a worldwide forum.. and there are many areas of low internet speed.

in post#5 now I edited your post so that there is a thumbnail, so not the whole 6MBytes need to be downloaded every time a member opens this thread.

Klaus

Paul678

Newbie level 6
Ok, but if we want to find the "Zero", we have to find the value of "s" that makes the numerator 0, right?

So wouldn't that be s=-(1/T2)? And wouldn't the "Poles" in the denominator, be at zero, and s=-(1/T1)?

sutapanaki

It's a typo or inaccurate writing. Obviously he uses T as a notation which should correspond to the time constant of the zero or poles. And there is one pole at 0, an integrator.

Paul678

Newbie level 6
It's a typo or inaccurate writing. Obviously he uses T as a notation which should correspond to the time constant of the zero or poles. And there is one pole at 0, an integrator.
So do you agree that in this case, the zero would that be at s=-(1/T2)?

And that the "Poles" in the denominator, would be at zero, and s=-(1/T1)?

sutapanaki

Yes. The reciprocal of time has the units of frequency and poles and zeroes are measured in frequency.

Paul678

Newbie level 6
Correct me if I am wrong, but it looks to me that for a PLL that I designed, that the open loop
unity gain frequency (0dB) appears to be the same as the closed loop bandwidth frequency.

And this frequency is also where the phase inflection point occurs, or where the open loop phase
margin is highest.

I believe Banerjee's book mentions this. But is this true for all PLLs, or just some of them?