Jim cage
Full Member level 2
measurement of peak to average
Hi,
I dont quiet understand the definition of peak to average ratio.
Suppose my DAC outputs a signal with 10dB peak to average.
If I measure the signal on the oscilloscope, will I see the peak signal 3.16 times (10dB) higher then the rms signal?
example:
Rms = 0.1V
Peak to Peak = 1V ===> Peak = 0.5V
-------
PAR=20*log10(0.5/0.1)=13.96dB
But from RF power prespective:
Prms ~ (0.1V)^2
Ppeak ~ (0.5V/sqrt(2))^2
-------------
PAR=10*log10{[(0.5V/sqrt(2)]^2 / [(0.1V)^2]}
---> PAR= 10.96dB
Can someone please clarify this issue?
Appriciate the answer,
Jimmy
Hi,
I dont quiet understand the definition of peak to average ratio.
Suppose my DAC outputs a signal with 10dB peak to average.
If I measure the signal on the oscilloscope, will I see the peak signal 3.16 times (10dB) higher then the rms signal?
example:
Rms = 0.1V
Peak to Peak = 1V ===> Peak = 0.5V
-------
PAR=20*log10(0.5/0.1)=13.96dB
But from RF power prespective:
Prms ~ (0.1V)^2
Ppeak ~ (0.5V/sqrt(2))^2
-------------
PAR=10*log10{[(0.5V/sqrt(2)]^2 / [(0.1V)^2]}
---> PAR= 10.96dB
Can someone please clarify this issue?
Appriciate the answer,
Jimmy