YooCanFly
Newbie level 3
Hello
I designed a LNA - passive mixer driven by a VCO.
I used a simple NMOS switch as passive mixer.
the LNA output is 900 MHz, has an amplitude of 5 mV.
The gate of the passive mixer is driven by VCO signal at 901MHz, with rail-to-rail amplitude.
Now, the output (IF signal) is a 1 MHz signal with an amplitude of 4 mV.
That is approx. -2 dB loss, isn't it?
From the books I read, it says -3 dB is the minimum loss I can have... and typically it will be -6 to -9 dB loss. Is my simulation incorrect?
Also, if I mix the LNA output with a differential VCO signals, I get a differential output with an amplitude of ~8mV
Since I started with 5 mV, that is actually a gain...
Am I missing something?
Let me know!
I designed a LNA - passive mixer driven by a VCO.
I used a simple NMOS switch as passive mixer.
the LNA output is 900 MHz, has an amplitude of 5 mV.
The gate of the passive mixer is driven by VCO signal at 901MHz, with rail-to-rail amplitude.
Now, the output (IF signal) is a 1 MHz signal with an amplitude of 4 mV.
That is approx. -2 dB loss, isn't it?
From the books I read, it says -3 dB is the minimum loss I can have... and typically it will be -6 to -9 dB loss. Is my simulation incorrect?
Also, if I mix the LNA output with a differential VCO signals, I get a differential output with an amplitude of ~8mV
Since I started with 5 mV, that is actually a gain...
Am I missing something?
Let me know!