Parallel LC circuit behaviour in dc

[Murugesh_89]

Hi,
For the below circuit what will be the circuit behaviour...



Thanks,
Murugesh

 

[KerimF]

As you know, in the steady state:

The capacitor current is zero.
And the currents of the coil and supply are the same and equal to 0.1/R where R is the total DC resistance of the loop (coil, supply and the connecting wires).

If R=0, the circuit and its behaviour are not real.

 

[Murugesh_89]

Since L and C are in parallel. Is there any possibility of producing oscillations as they see like LC tank circuit. Also the resistance of coil is 250E ohms.

 

[KerimF]

In this exact circuit, oscillations cannot be produced for many reasons.
First of all, please note that its LC tank is shunted by a voltage source which has an internal resistance close to zero. In other words, the parallel LC tank is 'shorted' by the voltage supply (it doesn't matter if it is DC, AC or both).

 

[Borber]

Oscillations happen only when voltage source is disconnected.

 

[Murugesh_89]

Will the inductor produces any magnetic field here? I am inserting a core metal in the center axis of inductor coil.
If yes, how long the magnetic field will be available and what would be its direction.

What is the purpose of capacitor? Will the inductor produces magnetic field without the capacitor?

 

[Murugesh_89]

Any answer please!!!

 

[Milad-D]

Of course, it does not oscillate. Here, the voltage of capacitor is fixed to the supply voltage and the current of inductor rises linearly with time: Ldi/dt=Vdd ==> i=(Vdd/L)t. therefore, it produce magnetic field and even even electric field (E prop. dB/dt). Because the capacitor is in parallel with supply, having or not having it, is not important.

 

[KerimF]

Yes, the inductor produces magnetic field without the capacitor.