Yes it requires power cycling, think this is intentional.So once it was triggered it will stay in "failure" mode.
Yes, the voltage at the Tl431 control pin will reach 2.5V when the output is 28V with those resistor values, which will then cause the cathode (top) pin to start conducting current above that point, turning on Q1 and triggering the SCR.................
If I use R7 as 10K and R9 as 980R. The out voltage when input is 28V will be 2.5V. Will this activa
You want a MOSFET with a low ON resistance (no more than a few milliohms) to minimize any voltage drop and I²R power dissipation during normal operation.I am thinking of using a P MOSFET to cut off the supply when 28 V is reached.
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This option should also work right? Seems ok
I ofcourse need to do my calculations yet. Choosing MOSFER with Vgs -4V and Id = 13 or 14A
Zener diodes have been invented for similar purposes...How can I control gate voltage so that it is less than 20V (Max Vgs) maybe somewhere around 10-12V (More acceptable value)
That device will dissipate 1.5W@10A so it may need a small heatsink since the case thermal resistance to air is a maximum of 50C/W.I am thinking of using Si4401DDY which has following specs
0.015 at VGS = - 10 V when Id = 16.1 Amps
0.022 at VGS = - 4.5 V when Id =13.3 Amps
Max Vds = -40V
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Depends upon the MOSFET and the maximum short circuit current available, as to whether the MOSFET will open before the fuse.And if you anyway have a MOSFET in your power path, consider replacing the fuse with active current sensing and cut the power using the MOSFET. A MOSFET is way faster than a fuse.
At 30V the D18 zener dissipation would be 28V times its current.
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