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Numerical - need solution to the task

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renzworldc

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numerical

A fully charged mobile phone with a 12v battery is good for 10mins talk-time. Assume that during talk-time, the battery delivers a constant current of 2A and its voltage drops linearly from 12 V to 10 V as shown in figure. How much energy does the battery deliver during this talk-time?
Ans: a. 220 J
b. 12 KJ
c. 13.2 KJ
d. 14.4 KJ
plz tel me how to solve it..?
 

Re: numerical

renzworldc said:
A fully charged mobile phone with a 12v battery is good for 10mins talk-time. Assume that during talk-time, the battery delivers a constant current of 2A and its voltage drops linearly from 12 V to 10 V as shown in figure. How much energy does the battery deliver during this talk-time?
Ans: a. 220 J
b. 12 J
c. 13.2 J
d. 14.4 J
plz tel me how to solve it..?

All ans are wrong!
E=mean(U)*I*t=11V*2A*600s=13200J (13.2KJ)
Mr. Admin, please do not give points for such kind of Post/Reply!!!! :cry:
 

numerical

yes I made a mistake in typing the ans..its KiloJoule instead of Joules..
nyways thanks.

if u don't want points u may better not post coz therz no compulsion.. why bothering the admin..
 

Re: numerical

renzworldc said:
yes I made a mistake in typing the ans..its KiloJoule instead of Joules..
nyways thanks.

if u don't want points u may better not post coz therz no compulsion.. why bothering the admin..
Sorry,
I wrote this comment in not good condition!
Please do not keep it in your mind.
Good lucks
 

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