reg_ic
Newbie level 6
hi:
when i sim the ldo , the current load i use the two ways:
case1: Rload=1.2/Iload ,and Iload will be given a spe value , maybe 50mA ,then
Rload=24(ou) . then in this case the finite Rload will give some impact to
the open loop gain . with the Iload increasing the impact will increase too!
case2: Iload=ideal current source , as we know this ideal current source will have
a infinite resistance . then in the case2 Iload will not introduce any impact
to the open loop gain !
i hope anyone can give some advice and make understand what makes different
between these two cases! many thx advance!
when i sim the ldo , the current load i use the two ways:
case1: Rload=1.2/Iload ,and Iload will be given a spe value , maybe 50mA ,then
Rload=24(ou) . then in this case the finite Rload will give some impact to
the open loop gain . with the Iload increasing the impact will increase too!
case2: Iload=ideal current source , as we know this ideal current source will have
a infinite resistance . then in the case2 Iload will not introduce any impact
to the open loop gain !
i hope anyone can give some advice and make understand what makes different
between these two cases! many thx advance!