Serial.begin(1200,SERIAL_7N1);
ASCII, hex, binary .... all are just 8 bits. Only the presentation is different.reads something like random hex numbers i guess
& as i read it must be ascii format i guess
Firstly, try "SERIAL_8N1" as it is far more commonly used.
If that doesn't fix it, please post your code so we can see how you interpret the data.
Are the numbers you see random, meaning different each time or is there some pattern to them? Knowing what the display shows will help with diagnosis.
Brian.
Hi,
ASCII, hex, binary .... all are just 8 bits. Only the presentation is different.
0x41 = 0b01000001 = "A"
Klaus
Every UART and every RS232 documentation will give this information:So how to know what is the start & stop bits
Hi,
Your informations are confusing.
I agree with the others: 7 data bits is quite unusual.
If you don't know ... who else should know?
Klaus
And, please, do a Internet search. It won't bite you
It may not be ASCII of course but if you see the expected result in a terminal program it probably is.i have started to read the (Read ASCII string) example in Arduino IDE Hope this help me to understand more about ASCII.
It may not be ASCII of course but if you see the expected result in a terminal program it probably is.
ALL data is just binary bits. ASCII is just a way of representing letters and numbers using those bits. It is a 7-bit code (although 8-bit and 16-bit 'unicode' extensions exist) so the bit pattern ranges from 0000000 to 1111111 or in hexadecimal 0x00 to 0x7F or in decimal 0 to 127 and each different number represents a different letter, number or symbol. You should be able to find an ASCII table that shows you how the binary converts to readable characters.
So the chances are that if you expected a reading 0f 0.123 you would receive bytes with values 0x30, 0x2E, 0x31, 0x32, 0x33 these being the ASCII values for '0' '.' '1' '2' and '3' respectively. You probably find an extra byte at the end 0x0A or 0x0D or both, these are the ASCII codes for a new line and carriage return that are often used to mark the end of the data and to move the cursor to the start of the next line in your terminal program.
If you are seeing the ASCII values instead of the character they represent, your display routine is not interpreting them properly, if you are using Arduino IDE you may be adding 'HEX' to the print routine for example when it isn't needed, or building strings with %x instead of %c.
Brain.
The internet if full of informations that detailed shows how a UART works.i cant understand what it means by 7Bits
Wrong!N(4E) its the start bit i guess
then + or - Ascii value in hex
0(30)
.(2E)
0(30)
0(30)
0(30)
g(67) stop bit i guess
Wrong!
0x4E is the ASCII code for 'N'.
0x67 is the ASCII code for 'g'.
The 'g' will be for grams, possibly the 'N' is used to indicate a minus (Negative) value, the ASCII for '-' is 0x2D.
Each byte has a start and stop bit, not the message as a whole. Each character is formed like this:
[start bit] < 7 data bits > < parity bit > [stop bit]. It is a serial data stream, the UART is designed to recognize the pattern of start and stop bits so it knows where to divide the stream up. Otherwise it would just look like a long pattern of '0' and '1' bits and it wouldn't be possible to tell where each byte started and ended. The start bit is always '0' and the stop bit is always '1'. There are 10 bits per character overall when you add the data, parity and framing bits. in your case, the Baud rate is 9600 which means there are 9600 bits per second (technically symbols per second but for your connection they are the same thing) so each bit is 1/9600 seconds long.
Brian.
Every character that you receive consists of Start bit, Data bits and Stop bit.
You can not see this structure in terminal application, but if you use logic analyzer you will be able to observe the exact structure.
With 7 bits you can "encode" first 127 characters from ASCII set (google ascii table).
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