mohdfayez
Junior Member level 2

suppose u have a DC voltage 'x'............anywhere between 0.3V to 7V......design a circuit in such a way that when this voltage x is given to this circuit the out put of the circuit will be a ramp voltage.
lets keep a switch in between the voltage source and this circuit
so basically when the switched is closed only then will the ramping start
the time of the ramping period should be variable...........most probably using a potentiometer...........and the range of the time should be from 0.1 to 10 seconds
so if u give an input voltage of lets say 4V to this circuit , as soon as the switch is closed that 4 volts should start ramping from 0V towards 4V and should attain a steady voltage after the ramping period is over
Can anyone help in this... with explaination coz I am not good at this.. help will be appreciated.. Thank you
Added after 40 minutes:
Required circuit is as given in attachment with output waveform
lets keep a switch in between the voltage source and this circuit
so basically when the switched is closed only then will the ramping start
the time of the ramping period should be variable...........most probably using a potentiometer...........and the range of the time should be from 0.1 to 10 seconds
so if u give an input voltage of lets say 4V to this circuit , as soon as the switch is closed that 4 volts should start ramping from 0V towards 4V and should attain a steady voltage after the ramping period is over
Can anyone help in this... with explaination coz I am not good at this.. help will be appreciated.. Thank you
Added after 40 minutes:
Required circuit is as given in attachment with output waveform