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Anyway, first thing is divide total capacity in bits by # of bits in each memory location. Let's say for example you meant 32 Mbyte = 256 Mbit. Divided by 32 bits that is 8M memory locations.
Then you take logarithm of that number, divide by logarithm of 2, and round up to nearest integer. In this case: log(8388608) / log(2) = 23. Read: 23 address bits needed.
For multiplexed addresses like with DRAM you would need half that number of address connections. Of course # of connections may be different depending on memory configuration, but that log(locations) / log(2) will quickly tell you how many address bits are needed. Note that this also works with other than base 10 logarithms!
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