Your circuit appears to be a capacitor-based voltage multiplier. Current is drawn from the supply in quick bursts at the peak of the AC waveform. It is difficult to obtain an average current level. You might get success if you:
* Install a full diode bridge which draws current from the supply
* Add a smoothing capacitor and resistive load
* Adjust values so that your initial load drops to half as many Amperes as it did before
* Doing the above steps splits the power equally to your measuring circuit, and to your initial circuit.
Then your measuring circuit draws smooth voltage and current waveforms, making it easy to calculate its average power draw. Multiply by 2 to obtain initial draw of your initial circuit.