Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

MC CDMA & rayleighchan

Status
Not open for further replies.

ammaralwazzan

Newbie level 6
Joined
Jan 13, 2010
Messages
14
Helped
4
Reputation
8
Reaction score
3
Trophy points
1,283
Activity points
1,392
hi,,

i am doing a code for MC CDMA system using rayleighchan
First of all i write a matlab code for OFDM-CDMA system. the following picture shows the structure of the system :

70365d1331057632t-ofdm_cdma_uplink_2_pilot.jpg


but i have some problem with the result :

CP = 0 , CP = 4 (1/16 from OFDM_Symbol_Size), CP = 8 (1/8 from OFDM_Symbol_Size), CP = 16 (1/4from OFDM_Symbol_Size)

change in size of cyclic prefix:
cp.jpg

why i got no change in the BER ? also when i change the size of FFT from 64 to 128 to 256 there is no change !!

any help will be appreciated
 

sorry i forget to explain that i used 802.11a as a standard for OFDM part , so the rayleighchan specification is :
bitrate = 20000000; % Bit Rate
ts = 1/bitrate; % ts is the sample time of the input signal, in seconds (bit rate is 10Mbps)
fd = 0.0001 ; % fd is the maximum Doppler shift, in Hertz
H = stdchan(ts, fd, 'itur3GPAx'); % Creat Channel

is this specifications is correct?

with :

delay = [0 110 190 410] * 1e-9;
path gains = [0 -10 -20 -23]; % in dB

thank you to every one
 

i need to get channel impulse response for rayleighchan fn? how?
 

Status
Not open for further replies.

Similar threads

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top