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Thanks, in that case, what we need to be able to do, is calculate the amount of power dissipated (wasted) in the solar panel itself by the current drawn from it.
..So, power = V*I…….
Well, we can measure the current…but how do we assess what the voltage is?....presumably the voltage is the nominal open circuit panel voltage minus the input voltage to the switching converter that’s downstream of it. Is this correct?
What is the open circuit panel voltage when the panel is under full sunlight?
Is this figure very different from the open circuit panel voltage when the panel is in dull daylight?
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