[SOLVED] Low voltage sharp cut out switch without relay for 6v battery

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samshoppy

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I am making a led light using 6v battery. I need a low voltage cutout circuit to protect battery from getting deep discharged. I have seen many circuits, but all switch off light slowly. I need a sharp cutout circuit which disconnect load at 4.7v , but without relay.
 

You can use a BJT or MOSFET for this. When the voltage is greater than 4.7V and the light should be on, the MOSFET/BJT should be turned on. When voltage reaches or falls below 4.7V, the MOSFET/BJT should be turned off. For the detection of the voltage, you can use a comparator circuit.

Hope this helps.
Tahmid.
 

A low voltage cutoff circuit was described in this thread: https://www.edaboard.com/threads/253486/. That one required a switch to be pressed to turn it on again after the battery has been recharged or replaced. I'm not sure if that is what you want.
 

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