vaibhavpawar
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Hi... I am newbie to Power Supply design.
I am using LM1117 - 5 Volt ( LM1117MPX-5.0 ) Texas IC in my application. Datasheet is saying dropout voltage is 1.2V.
Is it means we have to apply 5V+1.2V = 6.2V at input pin to get 5V. And if above is true, then if I apply 12 V, then considering dropout voltage I will get 12-1.2=10.8V at output.?
If it is true, then operating input voltage is suggesting 15V.
Pls suggest If we apply 15 V at input, then what voltage we will get if we use LM1117-5V. Is it 5V fixed or (15-1.2=13.8V).
Thanks in advance.
I am using LM1117 - 5 Volt ( LM1117MPX-5.0 ) Texas IC in my application. Datasheet is saying dropout voltage is 1.2V.
Is it means we have to apply 5V+1.2V = 6.2V at input pin to get 5V. And if above is true, then if I apply 12 V, then considering dropout voltage I will get 12-1.2=10.8V at output.?
If it is true, then operating input voltage is suggesting 15V.
Pls suggest If we apply 15 V at input, then what voltage we will get if we use LM1117-5V. Is it 5V fixed or (15-1.2=13.8V).
Thanks in advance.