Apr 10, 2013 #1 E ehsan_2593 Junior Member level 2 Joined Feb 17, 2013 Messages 23 Helped 2 Reputation 4 Reaction score 2 Trophy points 1,283 Location iran Activity points 1,401 hi I am searching for the light line equations to plot the EBG dispersion diagram in MATLAB. Can anyone help me?? Thanks
hi I am searching for the light line equations to plot the EBG dispersion diagram in MATLAB. Can anyone help me?? Thanks
Apr 29, 2013 #2 P PlanarMetamaterials Advanced Member level 4 Joined Jun 13, 2012 Messages 1,456 Helped 404 Reputation 812 Reaction score 382 Trophy points 1,363 Location Edmonton, Canada Activity points 9,824 The light line is non-dispersive, so you know that \[\beta = \frac{\omega}{c}\] Since the dispersion diagram plots Beta*d, you want to plot \[{\beta}d = \frac{\omega}{c}d\] Specifically, I plot my light line vs a Beta*d step of 5 degrees, for which I use the equation LightLine(Angle5) = (1/sqrt(eps*mu))*Angle5*(pi/180)/(2*pi*(d)) Which is a simple re-arrangement of the above equation to give the frequency of the light line at an angle Beta*d Last edited: Apr 29, 2013
The light line is non-dispersive, so you know that \[\beta = \frac{\omega}{c}\] Since the dispersion diagram plots Beta*d, you want to plot \[{\beta}d = \frac{\omega}{c}d\] Specifically, I plot my light line vs a Beta*d step of 5 degrees, for which I use the equation LightLine(Angle5) = (1/sqrt(eps*mu))*Angle5*(pi/180)/(2*pi*(d)) Which is a simple re-arrangement of the above equation to give the frequency of the light line at an angle Beta*d
Apr 30, 2013 #3 E ehsan_2593 Junior Member level 2 Joined Feb 17, 2013 Messages 23 Helped 2 Reputation 4 Reaction score 2 Trophy points 1,283 Location iran Activity points 1,401 PlanarMetamaterials said: The light line is non-dispersive, so you know that \[\beta = \frac{\omega}{c}\] Since the dispersion diagram plots Beta*d, you want to plot \[{\beta}d = \frac{\omega}{c}d\] Specifically, I plot my light line vs a Beta*d step of 5 degrees, for which I use the equation LightLine(Angle5) = (1/sqrt(eps*mu))*Angle5*(pi/180)/(2*pi*(d)) Which is a simple re-arrangement of the above equation to give the frequency of the light line at an angle Beta*d Click to expand... hi Thank you for guidance
PlanarMetamaterials said: The light line is non-dispersive, so you know that \[\beta = \frac{\omega}{c}\] Since the dispersion diagram plots Beta*d, you want to plot \[{\beta}d = \frac{\omega}{c}d\] Specifically, I plot my light line vs a Beta*d step of 5 degrees, for which I use the equation LightLine(Angle5) = (1/sqrt(eps*mu))*Angle5*(pi/180)/(2*pi*(d)) Which is a simple re-arrangement of the above equation to give the frequency of the light line at an angle Beta*d Click to expand... hi Thank you for guidance