Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

led tube parellel/series connection

Status
Not open for further replies.

maxim10373

Advanced Member level 4
Joined
Feb 26, 2010
Messages
115
Helped
1
Reputation
2
Reaction score
2
Trophy points
1,298
Activity points
2,063
Dear All
I need to make an LED Tube light in five feet long,
I bought 60 nos 5050 SMD LED.so which is the sutable
connection is parellel or series ?How many LED can connect
in a parellel circuit 12 v dc and which resistor should use their?
I think to connect 60 nos LED in one row.
LED details;
smd led 5050
for.volt=3.6
for current=300ma
input v=12 or ?

Please reply
maxim
 

you can use 12vdc 20A power supply

and you need to connect 3LED's series.

if you using 24vDC 10A power supply,
and you could go with 6Led's series..
 
if you use 3 LEDs in series, volt drop = 3 X 3.6 = 10.8 V, Vsupply = 12, Volts to loose = 12 - 10.8 = 1.2V, therefore series resistor = 1.2/.3 = 4.0 ohms, so 20 chains @ .3A each, is a 20 X .3 = 12V, 6 A PSU. For 24V PSU, 6 LEDs in each chain, so 2.4 V to loose at .3 A = 8 ohms, so PSU for 10 chains = 24 V @ 3A.
Frank
 
sir,
There havn't more space for put a big powersupply.
can I connect this 220v series

Thanks
maxim
 

If you connect all 60 in series these will take 60 X 3.6 = 216 Volts at .3 A. But you have AC, so you need a bridge rectifier, to turn the AC into DC. and you need a 230-216 = 14Volts to loose at a current of .3A = 14/.3 = 47 ohm resistor which will dissipate .3 X14 ~ 5W.
BEWARE THIS STUFF IS DANGEROUS!!!!
Frank
 

Status
Not open for further replies.

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top