By looking at the circuit operation point, you can see that AC analysis is actually working at zero transistor current.It calculates the gain for an infinitesimal small input voltage at the actual bias point, giving about no gain at zero transistor current.
I believe that you measured Ic somehow, just noticed that no current waveform is shown in the thread, so we can't know how the observed waveform is different from expectation.Please refer to the current probe V_IP1
AC analysis is actually working at zero transistor current.
consider the simulation of high-Q oscillators. These also require very long transient simulations; a Q of 10 000 suggests that the turn-on transient time starting from a zero initial state will be of the order of 10 000 cycles of the oscillation period
I say that AC analysis is performed in your circuit with no transistor current and hence no gain.I could not understand the above statement.
Why series R? Coil resistance can be expected very small for a 100 MHz class C amplifier, parallel R is representing the actual amplifier load. The L and C values in the circuit are far off from suitable values, though.You wrongly show "R Tank" parallel to the tank instead of in series with the inductor.
If "R tank" is the load then it should be called "R load". It should be capacitor-coupled and not shorting the DC of the transistor's collector to the supply voltage. A load of only 10 ohms is not suitable for a low power little transistor.Why series R? Coil resistance can be expected very small for a 100 MHz class C amplifier, parallel R is representing the actual amplifier load. The L and C values in the circuit are far off from suitable values, though.
As already mentioned, the actual L and C values are arbitrary and meaningless. So is the R load. Having this said, we can state that the circuit topology is basically correct. There's no (or very little) DC voltage drop across the inductor, respectively no AC coupling for the load needed. The collector voltage swings symmetrically above and below the supply voltage level.It should be capacitor-coupled and not shorting the DC of the transistor's collector to the supply voltage. A load of only 10 ohms is not suitable for a low power little transistor.
We use cookies and similar technologies for the following purposes:
Do you accept cookies and these technologies?
We use cookies and similar technologies for the following purposes:
Do you accept cookies and these technologies?