If the drain and source are connected directly by external wiring then it becomes a short. It's no longer a switch - it is just a short.
In the first circuit you showed, you must connect a resistor between the gate and the source. The MOSFET has a small gate capacitance and if the gate is not pulled low, that capacitance isn't discharged. The MOSFET has an insulated gate. So, to turn it off, you must discharge the gate capacitance and apply logic 0 to the gate, just removing the positive supply won't do.
Hope this helps.
Tahmid.
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PS. The gate has a maximum allowable voltage (with reference to the source). Usually this is 20V or 30V. So, in the circuit shown, you're connecting the gate to +200V. This would damage the MOSFET.