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[SOLVED] Inductor with differential port in ADS

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Hamid.Kiumarsi

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Dear all

I have encountered a problem for simulating a very simple lumped inductor in ADS schematic.
The picture of schematic is attached.



I am simulating this at 100 MHz, therefore with L=1nH, Q should be 50.
Using two single ports at the terminals of inductor is easy and gives the correct results. However when I am assigning differential port to the inductor S11 is something like -0.02dB.
It should be possible to get the correct result with differential port. I set the Zdiff of the port to 100 ohm and it didn't work either.

What am I doing wrong in my simulation?

waiting for your kind help
 

jackreloaded

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I don't know how your current setup can work, but **broken link removed**and here how you can use the ADS momentum to define each port type
 

Hamid.Kiumarsi

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Dear jackreloaded,

Thanks for reply. The links that you put in your post are for Momentum and actually I set up this simple schematic because I had this differential port problem in Momentum. Then I tried to understand that which part of my setting is wrong.

I drew an inductor and assigned a differential port to it in the same way as explained in the Momentum help document.
then I obtained s1p (one-port S parameters) for my inductor. S11 (dB) from Momentum results is -0.3dB! (I suppose that this should not be the S11 of my inductor)

Is this -0.3dB for differential port normal?
What pint am I missing in here?

---------- Post added at 13:36 ---------- Previous post was at 13:33 ----------

The correct value would be - 0.002dB
What value do you expect?

Thanks for reply,
Why the correct value is this?
Most probably I am confusing the single mode S parameters with mixed-mode ones.
Could you explain in detail that why S11 is not like -40dB?

By the way, Zdiff=100 ohm here is correct, right?
 

V

volker_muehlhaus

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Could you explain in detail that why S11 is not like -40dB?

I see where your misunderstanding is.

For the two port case, your impedance into the circuit is 1nH + 0.012 Ohm + port impedance on the other side.
For the one port case, your impedance into the circuit is 1nH + 0.012 Ohm.

So for the one port case, you see approximately a short circuit and get S11 ~ 0dB. This is the correct result for a one port simulation, if the inductor has small value and small series resistance.
 

Hamid.Kiumarsi

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Dear volker_muehlhaus

Really thanks for your detailed explanation.

Now everything is clear.
Just one question: is Zdiff=100 ohm correct?
 

V

volker_muehlhaus

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Just one question: is Zdiff=100 ohm correct?

The value is only relevant if you want to look at these S-parameters in the data display.

If you use the inductor results in the circuit, or calculate the L/Q values from the simulation results, the port impedance does not matter. You can use 50 ohm or 100 ohm, it makes no difference.
 

Hamid.Kiumarsi

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volker_muehlhaus

Dude thank you for explanation.

Regards,
Hamid
 

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