/*
*********************************************************************************************************
* CONVERT A FLOATING POINT NUMBER TO STRING WITH 1 DECIMAL PLACE
*
* Description : This function converts a floating point to a null terminated string
* with 1 decimal place.
*
* Examples:
*
* float f = 9.567;
* ftoa(&s[0], f); //s[]={'9','.','5', 0}
* float f = -0.189;
* ftoa(&s[0], f); //s[]={'-', '0', '.', '1', 0}
* Arguments : 'unsigned char* buf' is the pointer to the string holding the conversion result
* 'float f' is the input floating point
* Returns : None
* Notes : This routine modified from itoa10() in ..\sample\misc folder of ht-picc
* If more decimal places required, modify the last section of this code
* Range of f in (-3,276.7, 3,276.7)
* This function doesn't print result like 0.0. Instead, a single '0' got printed.
*********************************************************************************************************
*/
void ftoa(unsigned char *buf, float f) {
unsigned int rem;
unsigned char *s,length=0;
int i;
i = (int)((float)f*10);
s = buf;
if (i == 0){
*s++ = '0';
*s=0; //null terminate the string
} else {
if (i < 0) {
*buf++ = '-';
s = buf;
i = -i;
}
//while-loop to "decode" the long integer to ASCII by append '0', string in reverse manner
//If it is an integer of 124 -> string = {'4', '2', '1'}
while (i) {
++length;
rem = i % 10;
*s++ = rem + '0';
i /= 10;
}
//reverse the string in this for-loop, string became {'1', '2', '4'} after this for-loop
for(rem=0; ((unsigned char)rem)<length/2; rem++) {
*(buf+length) = *(buf+((unsigned char)rem));
*(buf+((unsigned char)rem)) = *(buf+(length-((unsigned char)rem)-1));
*(buf+(length-((unsigned char)rem)-1)) = *(buf+length);
}
/* Take care of the special case of 0.x if length ==1*/
if(length==1) {
*(buf+2) = *buf;
*buf = '0';
*(buf+1) = '.';
*(s+2)=0; //null terminate
} else {
*(buf+length) = *(buf+length-1);
*(buf+length-1)='.';
*(s+1)=0; //null terminate
}
}
}