IAR AVR C, Low/High byte of INT variable

Status
Not open for further replies.
D

Diamant

Newbie level 6
Joined
Oct 23, 2003
Messages
14
Helped
0
Reputation
0
Reaction score
0
Trophy points
1,281
Activity points
113
Need access to bytes of integer (16 bit).

I can do this in case if I know the integer address:
char *variable1 = (char*) 0xXXX; (address of integer)
char *variable2 = (char*) 0xXXX+1; (address+1 of integer)

is there any other way?
char *variable1=(char*) IntVariable; -could not be compiled

Moving integer left/right to receive Low/High byte is not god idea for me.

...Need help of advanced programmer...
 

The better is to do it via union

typedef struct chara
{
char char1;
char char2;
} chars ;

typedef union tall
{
int16 intn ;
chars charn;
} mynumber;

mynumber tnum1.intn = 65535;
char first_byte = tnum1.charn.char1;
char second_byte = tnum1.charn.char2;
 

What about this:

union
{
int integer;
unsigned char bytes[2];
}variable;

variable.integer to access it as an integer
variable.byte[0] and variable.byte[1] to access it bytewise

hope this is useful for you

Sorry for my post repeating artems answer, I could not see it while I typed this
 

Thanks a lot, this is the perfect way out!!!
I forgot about unions...

off: going to read more about unions.
 

debug has been successfull, thanks again
 

Or about this:

int integer;
char byteHi, byteLo;

byteHi = integer / 256;
byteLo = integer % 256

----------------------
or
byteHi = integer >> 8;
byteLo = integer;
 

Eskimo, this code needs additionals variables in memory to be created, I havent got them at all
 

Status
Not open for further replies.

Similar threads

Menu
Log in
Register
Cookies are required to use this site. You must accept them to continue using the site. Learn more…