how to use two 4bit multipliers to make up a 8bit multiplier

[red_0220]

Hi all,
Could you tell me how to use two 4bit multipliers to make up a 8bit multiplier?
thanks.

 

[ebuddy]

Re: how to use two 4bit multipliers to make up a 8bit multip

Will it allow AND/OR gates to be part of the soultion.? A good way to find out is to use synthesis tool to do the experiment and see what result it gives you. If synthesis tool can't do it, then it is most likely not doable. Post the result if you find one.

 

[raja.mst]

Re: how to use two 4bit multipliers to make up a 8bit multip

we can do it using 4 4-bit multipliers? and 3 Ripple Carry adders.

 

[red_0220]

Re: how to use two 4bit multipliers to make up a 8bit multip

we can do it using 4 4-bit multipliers? and 3 Ripple Carry adders.

Can you tell me how to do it?
Thanks.

Added after 1 minutes:

we can do it using 4 4-bit multipliers? and 3 Ripple Carry adders.

Can you tell me how to do it?
Thanks.

Added after 2 minutes:

To raja.mst

Can you tell me how to do it?
Thanks.

Added after 5 minutes:

we can do it using 4 4-bit multipliers? and 3 Ripple Carry adders.

Can you tell me how to do it?
Thanks.

 

[kforkarim]

Re: how to use two 4bit multipliers to make up a 8bit multip

Hey Raj,
Can you tell us how you implement this?
Thanks

 

[bunalmis]

Re: how to use two 4bit multipliers to make up a 8bit multip

Same as paper and pencil method.

a,b,c,d are four bits. ab and cd are 8 bit.

ab x cd = (b x d) + (a x d)<<4 + (c x b)<<4 + (a x c)<<8

 

[red_0220]

Re: how to use two 4bit multipliers to make up a 8bit multip

Same as paper and pencil method.

a,b,c,d are four bits. ab and cd are 8 bit.

ab x cd = (b x d) + (a x d)<<4 + (c x b)<<4 + (a x c)<<8

If I want to make up 16 bit multiplier by 4 bit multiplier.
Need Sixteen 4 bit multiplier at least?

thanks