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how to send 2 byte of data through uart

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xilinx1001

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Hi,

I need to send 2 bytes of data thorough uart.

But by standard protocol I can send only 1 byte of data.

I am using some code like this for send 1 byte.

Code:
process (stCur, rdaSig, dboutsig,tClk1)
		begin
			case stCur is
-------------------------------------------------------------------------
--
--Title: stReceive state 
--
--Description:	This state waits for the UART to receive data.  While in
--				this state, the rdSig and wrSig are held low to keep the
--				UART from transmitting any data.  Once the rdaSig is set
--				high, data has been received, and is safe to transmit. At
--				this time, the stSend state is loaded, and the dbOutSig 
--				is copied to the dbInSig in order to transmit the newly
--				acquired parallel information.

                             
-------------------------------------------------------------------------	
				when stReceive =>
					rdSig <= '0';
					wrSig <= '0';
--					if rdaSig = '1' then
					if(dbOutSig= x"73")then
--					trig1<='1';
					dbInSig <=distance(7 downto 0);
					stNext <= stSend;
					elsif(dbOutSig= x"74")then
--					trig2<='1';
					dbInSig <=distance2(7 downto 0);
					stNext <= stSend;
					
					else
					stNext<=stReceive;
					end if;
					
					
					
				
							
-------------------------------------------------------------------------
--
--Title: stSend state 
--
--Description:	This state tells the UART to send the parallel 
--				information found in dbInSig.  It does this by strobing 
--				both the rdSig and wrSig signals high.  Once these 
--				signals have been strobed high, the stReceive state is 
--				loaded.
--
-------------------------------------------------------------------------
				when stSend =>
					rdSig <= '0'; 
					wrSig <= '1';
					
					stNext <= stStop;

				when stStop =>
				wrSig <= '0';
           

			end case;
			
		end process;
end Behavioral;


when I am trying to send 2 bytes of data, I should again go to stReceive from stStop.

But when I am trying it the uart data is transmitting continuously

Can anyone suggest me, how can I do that for transmitting 2 bytes of data


Thanks in adavance
xilinx1001
 

You need a counter! And should do something like:

Code:
while(counter!=0)
{
send_byte_uart;
counter-=1;
}

Alternatively you can use a state machine. In state 0, you send byte 1, in state 1 you send byte 2, in state 3 you don't send anything.

You also need some kind of flag to signal that the uart transmission is complete, so you can put the next byte.
 

Hi,

Thank you for ur reply.
Yes, you idea is nice. But I need to transmit data when ever I press s.
Can you give me suggestion about this

Thanks in adavance
xilinx1001
 

Yes, reset the counter every time you press s.

If s is a character you receive on uart, just compare the received characters with the value of s (in ascii "s" is 0x73) and when they match, reset counter, or state machine if you go that way.
 
Last edited:

Hi,

Thanks for ur reply.

what is read signal(rdsig) and write signal (wrsig) in UART?

When I need to make these signal 0 and1


Thanks in adavance
xilinx1001
 

Hi,

I wrote the code something like this which is not working

please comment on it


when s1 =>
rdSig <= '0';
wrSig <= '0';

if rdaSig = '1' then
if dbOutSig <= X"73" then
dbInSig <= cm( 15 downto 8) ;
next_state <= s2;
else
next_state <= s1;

end if ;


-- if rdaSig = '1' then

if dbOutSig <= X"74" then

dbInsig <= cm2( 15 downto 8) ;
next_state <= s2;
else
next_state <= s1;

end if;
end if ;

when s2 =>
rdSig <= '0';
wrSig <= '1';
next_state <= s3 ;


when s3 =>

rdSig <= '1';
wrSig <= '0';


if rdaSig = '1' then
if dbOutSig <= X"73" then

dbInSig <= cm ( 7 downto 0 ) ;
next_state <= s4;
else
next_state <= s3;
end if ;



if dbOutSig <= X"74" then
dbInSig <= cm2( 7 downto 0 ) ;
next_state <= s4;
else
next_state <= s3;
end if ;
end if ;


when s4 =>
rdSig <= '0' ;
wrSig <= '1' ;
next_state <= s5 ;

when s5 =>
rdSig <= '1' ;
wrSig <= '0' ;
next_state <= s5 ;


end case;
end if ;
end process;
 

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