Oct 31, 2010 #1 E elvis0206 Junior Member level 1 Joined Oct 21, 2010 Messages 15 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,281 Activity points 1,400 I always get confused in finding the average power maximum power and the maximum instantaneous power dissipated in the transistor, which is an Emitter-Follower device ,for different cases. case1: Iq=[Vcc-Vce(sat)]/R case2: Iq<[Vcc-Vce(sat)]/R case3: Iq>[Vcc-Vce(sat)]/R It is great for you to give detailed explanation for it!!! and thanks a lot for you
I always get confused in finding the average power maximum power and the maximum instantaneous power dissipated in the transistor, which is an Emitter-Follower device ,for different cases. case1: Iq=[Vcc-Vce(sat)]/R case2: Iq<[Vcc-Vce(sat)]/R case3: Iq>[Vcc-Vce(sat)]/R It is great for you to give detailed explanation for it!!! and thanks a lot for you
Nov 9, 2010 #2 S SkyHigh Advanced Member level 1 Joined Jan 13, 2005 Messages 431 Helped 79 Reputation 158 Reaction score 28 Trophy points 1,308 Activity points 7,319 Max average power = iq rms x Re + ic rms x Rc Max instantaneous power is also known as peak power = iq peak x Re + ic peak x Rc
Max average power = iq rms x Re + ic rms x Rc Max instantaneous power is also known as peak power = iq peak x Re + ic peak x Rc