how to extract resistance from IV graph in origin

[aapirzado]

Hi All,
I need to know how one can extract the value of resistance from IV graph in Origin. I just plotted V and I on x-axis and y-axis respectively. I wonder there is some easy way to extract the resitance?
Thanks is advance,

 

[MahmoudHassan]

say attached figure
say we have VI plot
Resistance (Impedence) = volt / current
so for our graph
this is similar to take slope
R = Delta V/ Delta I
Delta V = v2 -v1
delta I = I2 - I1
where I1 and V1 for the same point 1
and I2 and V2 for the same point 2

for the figure attached
resistance =( v2 - v1)/(I2 - I1)
= (4-2) / ((2-1)*10^-3) =2000= 2Kohm
as current is plotted in Milli Amper (mA)

 

[Junus2012]

put the current in the X-axis and the voltage in the y axes. then take the slop of the line which is I/V and this represents the resistor value

Hi All,
I need to know how one can extract the value of resistance from IV graph in Origin. I just plotted V and I on x-axis and y-axis respectively. I wonder there is some easy way to extract the resitance?
Thanks is advance,

 

[Element_115]

put the current in the X-axis and the voltage in the y axes. then take the slop of the line which is I/V and this represents the resistor value

I*R= V --> R= V/I
Slope = Rise / Run --> y/x

 

[MahmoudHassan]

off course it is shown in the attached schematic .... R = V/I