It's very simple. The red plot shows the R-to-V characteristic of any voltage divider circuit, that implements endpoints of 0.5 and 9.5 V e.g. the said proposal 1 and 2. The blue plot shows a linear circuit with current source. The plots visualize the simple fact, that you can't have both linear characteristic and 0 to infinity resistance range.I don't fully understand your post #19.
Did you undertstand, that the linear transfer function implies a resistance range of 0 to 23.3 kohm (if 11 kohm is set to 4.75 V)?The only issue now is that it has still a non-linear transfer function; so now I will focus in make it linear replacing R1 by a Current_Source.
Barry:
a) What will happen in the REAL_WORLD (not SIMULATIONS) if the R_DUT goes above 666 Ohms? (Will it break the PNP Q1 transistor? or Does it simply will not conduct as I understood? :shock:
b) Why in my simulation can I increase the R_DUT above 666Ohms and the transistor continues turned ON and the voltage across R_DUT continues increasing above +5V? :???:
Thanks!
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