Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

How to charge lead battery

Status
Not open for further replies.

pinkfloyd11

Newbie level 5
Joined
Jan 26, 2010
Messages
8
Helped
0
Reputation
0
Reaction score
0
Trophy points
1,281
Activity points
1,331
Hello I should charge load battery.

I would avoid high current charge when the battery plugged is very discharged

Is correct the schematic?

Why I drop so much voltage on LM317 configured as costant current regulator?

Thanks

HTML:
[url=https://obrazki.elektroda.pl/13_1339079766.png][img]https://obrazki.elektroda.pl/13_1339079766_thumb.png[/img][/url]
 

Attachments

  • Cattura.PNG
    Cattura.PNG
    37.5 KB · Views: 107

There is a constant current flowing through the load (20Ω resistor). So, the voltage across the resistor and hence the output voltage of the LM317 must be (0.474289*20)V=9.486V [as V=IR]. Your simulation shows that this is the output voltage. As, the input voltage is 13.5V and the output must be 9.486V for the constant current through the load, the remaining voltage is dropped by the LM317 by dissipating the energy as heat.

Hope this helps.
Tahmid.
 

A lead-acid battery should be charged from a constant voltage source. To limit the maximum current a simple series resistor is quite sufficient.
 

Status
Not open for further replies.

Similar threads

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top