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How to calculate the value of Indunctance in tsmc 0.18models

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ilovebow

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I use the "TSMC_CM018RF_INDS2_SYM"

The parameter need to set is " W nr rad ", what's thses parameters meaning

And How can i get the L value from those values?

Thank you very much
 

Re: How to calculate the value of Indunctance in tsmc 0.18mo

as far as i know the W is the width of the metal , N number of turns , and rad is the radius of the inductor
about how to get L , in the model there is an equation relate all these paramters toL

check it

Khouly
 

Re: How to calculate the value of Indunctance in tsmc 0.18mo

yeah, I have check the model files.

But there are two equations about L value.

One is only depended on "rad" and other one is depended on "nr ". As showing below

3x

; .subckt spiral_rad : Typical model for Inductance varies with radius
; .subckt spiral_turn : Typical model for Inductance varies with turns
;
; Model name turn rad (um)
; low high low high
; ------------------------------------------------------
; spiral_turn 2.5 7.5 60 60
; ------------------------------------------------------
; spiral_rad 4.5 4.5 30 150
; ------------------------------------------------------
;
; **spiral_turn: only discret turn numbers are available,including 2.5, 3.5, 4.5, 5.5, 6.5 and 7.5
; **spiral_rad: scaled by inner edge-to-edge radius, the details see SPICE document
;
;*************************************************************************************************
define TSMC_CM018RF_RF_SUBCKT_inda_rf ( top bottom)
parameters nr=2.5
; L = L(nr)
L:ls top n2 L=(0.40425*nr*nr-0.995*nr+2.3295)*1.0e-9*l_fac
R:rs n2 bottom R=(1.029*nr-0.746)*rm6_fac
C:cs top bottom C=(6.243*nr+5.803)*1.0e-15*cs_fac
C:cox1 top n1 C=(32.526*nr-14.405)*1.0e-15*cm6_fac
C:cox2 bottom n3 C=(32.683*nr-25.194)*1.0e-15*cm6_fac
C:csub1 n1 0 C=(11.561*nr+9.1643)*1.0e-15*csub_fac
C:csub2 n3 0 C=(11.561*nr+9.1643)*1.0e-15*csub_fac
R:rsub1 n1 0 R=(-18.489*nr+487.7)*rsub_fac
R:rsub2 n3 0 R=(-18.489*nr+487.7)*rsub_fac
end TSMC_CM018RF_RF_SUBCKT_spiral_turn

define TSMC_CM018RF_RF_SUBCKT_indb_rf ( top bottom)
parameters rad=3e-05
; L = L(rad)
L:ls top n2 L=(0.0916*rad*1.0e6+0.7461)*1.0e-9*l_fac
R:rs n2 bottom R=(0.031*rad*1.0e6+1.8553)*rm6_fac
C:cs top bottom C=(0.2289*rad*1.0e6+21.092)*1.0e-15*cs_fac
C:cox1 top n1 C=(0.811*rad*1.0e6+79.292)*1.0e-15*cm6_fac
C:cox2 bottom n3 C=(0.9108*rad*1.0e6+59.886)*1.0e-15*cm6_fac
C:csub1 n1 0 C=(0.1611*rad*1.0e6+50.779)*1.0e-15*csub_fac
C:csub2 n3 0 C=(0.1611*rad*1.0e6+50.779)*1.0e-15*csub_fac
R:rsub1 n1 0 R=(-0.575*rad*1.0e6+433.3*rsub_fac
R:rsub2 n3 0 R=(-0.575*rad*1.0e6+433.3*rsub_fac
end TSMC_CM018RF_RF_SUBCKT_indb_rf
 

Re: How to calculate the value of Indunctance in tsmc 0.18mo

u see these are the equations that relate the inductor PI model to its dimenssions

khouly
 

Re: How to calculate the value of Indunctance in tsmc 0.18mo

I know it use the inductor PI model. but the each equation only depended one parameter, and i still can't find out the value
[

quote="khouly"]u see these are the equations that relate the inductor PI model to its dimenssions

khouly[/quote]
 

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