[SOLVED] how to access volatile char array through non volatile char pointer

scorrpeio · Dec 27, 2011

I have a function whose argument consist of a pointer to unsigned char.

Now, I want to pass an array of type volatile unsigned char. :!:

If I try to pass it directly, compiler doesn't allow me to do so. I think it needs typecasting to be done but I am not sure if it works. :sad:

I am searching about it on the google as well.

Can anyone here tell me what can be the probable way to do this?

horace1 · Dec 27, 2011

assuming you have

Code:

volatile unsigned char x[10]={'Z'};

and a function

Code:

void test(unsigned char *ch)

you can try

Code:

    test((unsigned char *) x);

scorrpeio · Dec 27, 2011

That is working.

I initially tried it in reverse way by which, normal pointer was casted to volatile pointer. that is why I did get an error

Enlightenment · Dec 27, 2011

I've fixed problems with some old compilers by dropping in a conversion to a "void pointer", such as (void *), before you cast to the final pointer type.

There are advantages and disadvantages of void pointers, so be careful to not abuse the use of them.

Disadvantages of using void* pointers in C - Stack Overflow

What is the use of a void* pointer? - C / C++

search internet for more discusion on this topic.

[SOLVED] how to access volatile char array through non volatile char pointer

scorrpeio

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[SOLVED] how to access volatile char array through non volatile char pointer

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