inductors measuring dmm
Anand,
For sinusoidal signals, you can use modified ohm's law where you use impedance instead of resistance. So, as long as you are looking as AC steady state, you can simply measure voltage levels.
If you really want to do this in time domain, you can. It's straight forward... but it's also a page and a half worth of derivation in my circuit analysis book. Using impedance is a short cut.
As an example:
1V P-P sine wave at 100KHz is connected to a series connected 1Kohm resistor and 1mH inductor. Voltage across the inductor is 1V * voltage divider equation between the 1K resistor and 1mH inductor.
Impedance of the inductor is j*2*pi*100e3*1e-3 = 628.3j.
So, total impedance is 1000 + 628.3j.
Voltage across the inductor is ZL / (R + ZL) * 1V = 628.3j / (1000+628.3j) * 1V.
Since we are only measuring the P-P voltage and take a magnitude of the above and you get 628.3/(1181) = .532V.
P-P voltage across is 1mH is .532V. Your DMM will measure RMS voltage, so your measurement is squrt(2) off (.376V).
Try it out on a spice simulator is you want to double check....
Also, if you want to do the time domain analysis, look it up in your electric circuit analysis book.
Cheers