Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

How does a capacitor work in this circuit?

Status
Not open for further replies.

autominus

Newbie
Joined
May 26, 2021
Messages
3
Helped
0
Reputation
0
Reaction score
0
Trophy points
1
Activity points
35
What are the main functions of a capacitor C30 in this buck step-down converter?

BZrIP.gif
 

The arrangement of the converter has it referenced to the positive supply rail. The load as well. C28 is the typical position for a reservoir cap. However C30 also performs the same job even though it's referenced to 0v ground.

The designer could have been creating a safeguard by putting in two caps. The solenoid being an inductive load is liable to generate spikes at odd times. So depending on what polarity Is the spike, one or the other cap can absorb it, since one is referenced to supply plus, the other cap is referenced to supply minus.
 

Thank you for the explanation.

I design a very similar circuit. My electronic circuit activates fan when processor heats up and then control rotation speed. The fan has a brushless motor with an internal motor controller - SUNON MF50100V1-1000U-A99, DC 5V

fan PWM control capacitor 2 with filtr EN.JPG


latex obliczenia EN.jpg

I calculated buck converter external components: L1 = 192uH, C1out = 80uF and C2in = 154uF.
I know that it is minimum value components. So, I'll use as: L1 = 330uH, C1out = 220uF, C2in = 220uF or 330uF.

I think that using capacitor C3 would be a good idea. But how to calculate its value?
 

I should like to propose an all-in-one solution. So I added jumper for setting the power supply.

When the fan with brushless motor is used, a jumper should be set to pin 1-2. The buck converter works fully.
2_buck.JPG

Whereas, when the fan which is compatible with PWM, a jumper should be set to pin 2-3. Capacitors work as reservoir and can absorb the spike.
2_pwm.JPG


So, what do you think?
 

Hi,

Without L1 but C1 and C3 installed you may expect hery high current peaks at the Mosfet. Not nice.

What is the Mosfet gate driving circuit? Is the 10R useful?

Klaus
 

I use Raspberry Pi to generate a PWM signal. Basic PWM generation on the Raspberry Pi only has two independent channels, which can be accessed via 4 pins: GPIOs 12 and 18 for channel 0, 13 and 19 for channel 1.
GPIO-Pinout-Diagram-2-mini.png

FAN Filtr.JPG



That's really interesting idea with all-in-one solution, Pavhek.
I just had an idea how to avoid high current peaks at the Mosfet. I could use dip switch, which will allow working circuit without L1, C1 and C3.
FAN Filtr 2.JPG

For fan which has a brushless motor: 1, 2, 3 pins are ON and 4 pin is OFF.
For fan which is compatible with PWM: 1, 2, 3 pins are OFF and 4 pin is ON.

Well, what do you think of my proposal solution?
 
Last edited:

Status
Not open for further replies.

Similar threads

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top