A decent rule of thumb will get you close:
C = I x dT/dV
C (in uF) = Amps x microseconds (between mains half cycles) divided by desired peak to peak ripple.
Lets see, assume 1,200 watts at 340v dc (= 3.5A) and 34v p/p ripple.
Assume 100 Hz from rectifier = 10,000uS hold up time between cycles
This is for both C4 and C7 as they are in series across the dc rail.
C = 3.5A x 10,000uS / 34v p/p ripple
1,029uF total
C5 and C7 will EACH need to be 2,000uF for about 10% ripple in 220v bridge configuration.
Voltage doubler configuration will require a bit more, but it gets complicated.