Help me convert this into formula

[smslca]

please convert the below(P) into formula using (m), or give an algorithm using (m) to get (P)

m=2, P=0
m=3, P=3
m=4, P=3+5
m=5, P=3+5+5
m=6, P=3+5+5+7
m=7, P=3+5+5+7+9
m=8, P=3+5+5+7+9+9
m=9, P=3+5+5+7+9+9+11
m=10, P=3+5+5+7+9+9+11+13
m=11, P=3+5+5+7+9+9+11+13+13
m=12, P=3+5+5+7+9+9+11+13+13+15
m=13, P=3+5+5+7+9+9+11+13+13+15+17
m=14, P=3+5+5+7+9+9+11+13+13+15+17+17
and so on

I did not understand how to evaluate it into a formula

 

[_Eduardo_]

Re: convert into formula

Let n = [m/3] ; [] mean integer part
and k = m mod 3 ; mod mean modulus (remainder of the integer divide m/3)

That is:
m --> n , k
3 --> 1, 0
4 --> 1, 1
5 --> 1, 2
6 --> 2, 0
7 --> 2, 1
8 --> 2, 2
9 --> 3, 0
...............


Then P(n,k) = n*(6*n-1) + k*(4*n+1) - 2

 

[smslca]

convert into formula

thanks for the replies