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Hall current sensor and its connection?

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treez

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Hello,
We are using ACS770LCB-050U-PFF-T hall sensor.
On page 5 of its datasheet it says the min load resistance from VIOUT to ground is 4700R. It also says the maximum load capacitance is 10nF.

Does this mean we have to connect at least 4700 (or lower value) from VIOUT to ground?
Also, does it mean that we may not connect more than 10nF from VIOUT to GND?

Why does the diagram on page 1 show no resistance from VIOUT to ground?

ACS770LCB-050U-PFF-T Datasheet:

https://www.google.co.uk/url?sa=t&r...et.pdf&usg=AFQjCNEj1QgkSJu44S5o_0ArNz8Zi1ZXTw

Also, why does the 'VIOUT' output need an RC filter as in the diagram on page one?...is it due to the high ripple output caused by the chopper stabilization technique?
 
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On page 5 of its datasheet it says the min load resistance from VIOUT to ground is 4700R. It also says the maximum load capacitance is 10nF.
Does this mean we have to connect at least 4700 (or lower value) from VIOUT to ground?
It's a min. value, means 4700Ω or higher value.

Also, does it mean that we may not connect more than 10nF from VIOUT to GND?
Yes. You should not.

Why does the diagram on page 1 show no resistance from VIOUT to ground?
Because it's not necessary, s. my 1st answer. Just the input impedance of the following stage should be ≥ 4.7kΩ.

Also, why does the 'VIOUT' output need an RC filter as in the diagram on page one?...is it due to the high ripple output caused by the chopper stabilization technique?
Don't think so. It's probably a filter against DC current fluctuations, or against noise.
 
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It can sink more than source. 10 vs 3mA

Hence

"Minimum pull-up resistor of 500 Ω, from VCC to VIOUT |
"RL VIOUT to GND 4.7 kΩ" (min)

typical bipolar (BJT) specs are asymmetric.
 
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