Mar 2, 2003 #1 C cdcll Full Member level 3 Joined Feb 15, 2002 Messages 163 Helped 8 Reputation 16 Reaction score 1 Trophy points 1,298 Activity points 1,199 I need help for how to get 24V/2mA from 4-20mA signal line, any recommendations and experiences are welcome.
I need help for how to get 24V/2mA from 4-20mA signal line, any recommendations and experiences are welcome.
Mar 2, 2003 #2 T techie Advanced Member level 3 Joined Feb 5, 2002 Messages 839 Helped 58 Reputation 116 Reaction score 9 Trophy points 1,298 Location Pakistan Activity points 7,805 You probably wouldnot get a full 24v, but I have seen circuits getting about 8 volts from this line. It also depends how much the loop of 4-20ma is powered up with.
You probably wouldnot get a full 24v, but I have seen circuits getting about 8 volts from this line. It also depends how much the loop of 4-20ma is powered up with.
Mar 2, 2003 #3 7 7rots51 Advanced Member level 4 Joined May 17, 2002 Messages 1,183 Helped 25 Reputation 50 Reaction score 12 Trophy points 1,318 Activity points 9,636 hello AD company have several AN on this,you can see the data sheet of AD*693 for lo0p p0wered m/a lo0p. NS also have several AN on this subject. bye
hello AD company have several AN on this,you can see the data sheet of AD*693 for lo0p p0wered m/a lo0p. NS also have several AN on this subject. bye
Mar 2, 2003 #4 flatulent Advanced Member level 6 Joined Jul 19, 2002 Messages 4,624 Helped 489 Reputation 980 Reaction score 151 Trophy points 1,343 Location Middle Earth Activity points 46,689 4 mA max The current drawn must be lower than 4 mA unless the data you are sending over the line will never be a value represented by low currents.
4 mA max The current drawn must be lower than 4 mA unless the data you are sending over the line will never be a value represented by low currents.
Mar 2, 2003 #5 LechU Member level 2 Joined May 16, 2001 Messages 51 Helped 0 Reputation 0 Reaction score 0 Trophy points 1,286 Location Poland Activity points 283 Found somewhere on the net Schematic foud somewhere on the net ...