Function return Array

Hi,

I have this function

There is some error on the coding. Anyone please can you help me?

Thank you.

You can use library function strcpy.


You cant return buff as its a local variable and will go out of scope!
If you dont want to use library function.

here is an example of Function that could get data from other function... hope this would help...

the program would allow the user to delete a number from the displayed array...

#include<stdio.h>
main()
{
int del(int *a, int value, int *size);
static int array[] = {11,12,13,14,15,16,17,18,19,20};
int num, i=10, c, found;
char exit;

do
{
clrscr();
printf("Original Array of Numbers\n");
for(c = 0; c < i ; ++c)
printf("%3d", array[c]);

printf("\n\nEnter a data to be deleted: ");
scanf("%d", &num);

c = i;
found = del(array, num, &i);

if(found == 1)
{
printf("\n%d is deleted from the array\n", num);
for(c=0; c<i; ++c)
printf("%3d", array[c]);
}
else
printf("Data not found");

printf("\nDo you want to delete another number(Y/N)?");
exit = getch();

}while(exit != 'n' && exit !='N');

}

int del(int *a, int value, int *size)
{
int i, c;
for(i = 0; i<*size; ++i)
{
if(a==value)
{
for(c = i; c<=*size-1; ++c)
a[c] = a[c+1];

*size = c-1;
return(1);
}
}
}

From K&R:


or

or

Hope this Helps,

Red