(Eb/N0) Overall calculation

[Bram Jester]

Hi Guys,

Just wondering if someone could help me out:

I have the following:
Eb/N0 uplink = 18.4dB
Eb/N0 downlink = 11.8dB

The formula that I am using is: (Eb/N0 uplink x Eb/N0 downlink) / (Eb/N0 uplink + Eb/N0 downlink)

I get 7.19dB

The answer is 10.9dB

I think my problem is that I have to convert dB to something, but I don't know how do I convert the dB so that I can use it in my equation?

Cheers,

 

[afz23]

Use this rule,
10*logX=value in dB,
Where log is to the base 10.

Find X for the values in dB,and substitute in the formula,you will get the answer,
Don't forget to reconvert the answer in dB .

 

[vfone]

Actually you have to convert dB to linear using: linear = 10^(dB/10)
So, 18.4dB = 69.18 linear
and 11.8dB = 15.13 linear
we get (69.18*15.13) / (69.18+15.13) = 12.41 linear
in dB = 10*LOG(12.41) = 10.9 dB

 

[Bram Jester]

Hey thanks for your help.

I do have another question. Still trying to get my head around Eb/N0.

Calculating Eb/N0 with a C/NO of 73.68dB, a bandwidth (fb) of 75Mbit/s. Is giving me -5.08dB

Is the formula Eb/N0= C/N0-10 LOG fb

Is this right? What am I missing?

 

[vfone]

I think you have to put the channel bandwidth in your equation, which is not the same thing as bit rate.

Eb/No(dB) = C/No(dB) - 10*LOG[Bit_Rate(bps)/BW(Hz)]

http://www.sss-mag.com/ebn0.html

 

[Bram Jester]

Thank mate.
I think that formula is actually:
C/N = Eb/No - 10LOG (B/fb)

I figured out what I did wrong to get my negative answer. I made a mistake early on in my Link Budget analysis that gave me an incorrect C/No.

The correct C/No was 106.1dB which in turn gave be an Eb/No of 27.35dB (and an Eb/No overall of 10.57)

Thanks again.

 

[vfone]

There are a lot of discussions on the Internet about this topic (also in the link above), and myself I gave up finding the right answer.
Is somehow related to the difference between S/No and C/No.
Very often the published equations looks like:

Eb/No(dB) = S/No(dB) + 10*LOG[BW(Hz)/Bit_Rate(bps)]
Eb/No(dB) = C/No(dB) - 10*LOG[Bit_Rate(bps)/BW(Hz)]