I have read in one book that shorting the base and collector of the transistor results in a diode connected transistor......................
can anyone explain in more detail to this..........?
You get a two-terminal device, which is acting as a diode.
It has, however, the rather low base-emitter breakdown voltage of about 7 V in reverse biased operation. To utilize a transistor as diode (may be meaningful e. g. to reduce the type count on a PCB), you should better use the collector-base diode with unconnected emiiter.
You get a two-terminal device, which is acting as a diode.
It has, however, the rather low base-emitter breakdown voltage of about 7 V in reverse biased operation. To utilize a transistor as diode (may be meaningful e. g. to reduce the type count on a PCB), you should better use the collector-base diode with unconnected emiiter.
thanks a lot....... but shorting collector and base (in case of npn) will the collector now act as n-type or p-type . if it is to act as diode it should act as p type isn't coz the emitter is already n-type i am really confused with this............. Please expalin me about this..................
thanks in advance.............
Added after 1 minutes:
FvM said:
You get a two-terminal device, which is acting as a diode.
It has, however, the rather low base-emitter breakdown voltage of about 7 V in reverse biased operation. To utilize a transistor as diode (may be meaningful e. g. to reduce the type count on a PCB), you should better use the collector-base diode with unconnected emiiter.