divide matrix in equal parts in matlab

Hello all
this is my matlab code as an output I am getting 1 matrix of 54*3 but instead of that i need 18 matrices of 3*3

like 1st 9 element will make 1 matrix than 10-18 will make another one and so on.

clc;
count=0;
Ci=zeros(0,0);
X=[0, 1/3, 2/3, 1, 1, 1, 1, 2/3, 1/3, 0, 0, 0, 1/3, 2/3, 1/3, 2/3];
Y=[1, 1, 1, 1, 2/3, 1/3, 0, 0, 0, 0, 1/3, 2/3, 2/3, 2/3, 1/3, 1/3];
Z=[12 13 1;
13 2 1;
13 14 2;
14 3 2;
14 5 3;
5 4 3;
11 15 12;
15 13 12;
15 16 13;
16 14 13;
16 6 14;
6 5 14;
10 9 11;
9 15 11;
9 8 15;
8 16 15;
8 7 16;
7 6 16];

for r=1:18;
I=Z(r,1);
J=Z(r,2);
K=Z(r,3);

sum=0;
P(1)=Y(J)-Y(K);
P(2)=Y(K)-Y(I);
P(3)=Y(I)-Y(J);
Q(1)=X(K)-X(J);
Q(2)=X(I)-X(K);
Q(3)=X(J)-X(I);

a=(P(2)*Q(3))-(P(3)*Q(2));
A=0.5*a;
d=4*A;
for i=1:3;
for j=1:3;
b=P(i)*P(j);
c=Q(i)*Q(j);
sum=b+c;
C=sum/d;
%matrix formation

v=count/3;
if(v==3)
x=floor(v);
else
x=floor(v)+1;
end
w=mod(count,3)+1;
Ci(x,w)=C;
count=count+1;

end
end
Ci

end

thQs in advance
cheers