Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

Differential logic in steering DAC

Status
Not open for further replies.

yefj

Advanced Member level 4
Joined
Sep 12, 2019
Messages
1,189
Helped
1
Reputation
2
Reaction score
3
Trophy points
38
Activity points
7,173
Hello,till now i am used to the logic of as we increase the number of currnt sources going thew resistor.
It thermometer or binary weighed.
BUt here we have some sort of subtraction between out put voltages and i cant see how this subtraction could make the starecase form of DAC where as we increase sumthing we get a largers voltage value.
It seems that this subtraction makes one side "fight" with the other
Thanks.

1600445757034.png

1600446019649.png
 

You would probably make two parallel R-2R ladders
to take the two "horns" of the differential current
"switch".

Settling time might be inferior to an emitter-steered
version, where one side of the pair is wasted to a
supply rail. If you need differential output then the
entire thing would be replicated with a logic phase
flip (e.g. the other side of the diff switch, this time).
The Miller kick from hard switching the base can
be a speed bump to get over, settling time wise.
 
  • Like
Reactions: yefj

    yefj

    Points: 2
    Helpful Answer Positive Rating
This is not what i asked, i asked:
we have some sort of subtraction between out put voltages and i cant see how this subtraction could make the starecase form of DAC where as we increase sumthing we get a largers voltage value.
It seems that this subtraction makes one side "fight" with the other
Thanks.
 

It doesn't, at the level you show. The arrangement
and its logic and summation method of N weighted
outputs, does.
 
  • Like
Reactions: yefj

    yefj

    Points: 2
    Helpful Answer Positive Rating
the proffessor in the video lecture says it is a logical output its a special kind of dac
1600455737054.png
 

I think, I guess what is your concern (hopefully).

m is some intermediate code and DAC ourput is taken differentially. Switches are differential, too.
So, for code 0,into branch Vop is flowing no current, while into Von full current. Opposite situation is for code 2^N-1, and LSB is then 2IR
 
  • Like
Reactions: yefj

    yefj

    Points: 2
    Helpful Answer Positive Rating
So if i understand correctly N is constant and m is the code :) cool
thanks alot :)
 

Yes, m is the code and N is the number of bits
 
  • Like
Reactions: yefj

    yefj

    Points: 2
    Helpful Answer Positive Rating
Status
Not open for further replies.

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top