First circuit is differential pair with current-source loads. It has good dynamic range (output swing).
Second one is differential pair with diode-connected loads. It has lower dynamic range.
Look on my piece. It can helps you
Only one thing you must account. Output swing Vswing = 2*Vout.1 (from my calculation)
First circuit is differential pair with current-source loads. It has good dynamic range (output swing).
Second one is differential pair with diode-connected loads. It has lower dynamic range.
Look on my piece. It can helps youView attachment 82488View attachment 82489
Only one thing you must account. Output swing Vswing = 2*Vout.1 (from my calculation)
you have supposed the maximum voltage for the differential amplifier with a current source load to approach Vdd, in reality this is the large signal char., for the small signal behavioural this voltage maximully is (Vdd-Vdss) because t he transistors must work in the saturation region
second thing, the voltage drop od the diode is (Vdss+vth) so you forgot to include the threshold voltage
any way the problem is solved and thank you once again