#### BlackOps

##### Full Member level 5

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i have developed simple problem, for example on the pic u see the graph of the Current which was applied to the capacitor... now i must know how will the Voltage graph look like...

Capacitor = 3µF

so:

v(t) = 1/C * (∫t0-t i(t')dt') + v0

the graph of I(t) on the interval from 0mS to 3mS is x^2, is parabola.

i can say that the V-t graph on interval from 3mS to 6mS will look like on picture... it will be straignt line. because: V(t) = 1/C * area of the rectangle ===> V(t) = (1/3 * 10^-6) * 3 * 10^-3 * 9 * 10^-3 = 9V...

but i am confused about how will look the graph on V-t from 0mS to 3mS interval...

and please derive the step by step integral equation for computing the expression from 0 to 3 ms

thanks, sometimes simple things make me confused

i will be very gratefull if u sketch correct graph and upload it here...